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#!/bin/sh
# prints out logs that are in dir1 but not in dir2
if [ $# -ne 3 ]; then
echo "usage: $0 arch dir1 dir2"
exit 1
fi
here=$(pwd)
arch=$1
dir1=$2
dir2=$3
fdir1=$here/${arch}-$dir1
fdir2=$here/${arch}-$dir2
ldir2=$(cd $fdir2; pwd | sed -e 's/e\./a./')
plus="$(echo $2 $3 | sed -e 's/ /+/g')"
of=$here/$arch-$plus.html
echo "<html><head><title>Logs that are in both $dir1 and $dir2</title>" >$of
echo "<h1>Logs that are in both $dir1 and $dir2</h1>" >>$of
echo "</head><body>" >>$of
cd $fdir1
logs=$(find . -name \*.log -o -name \*.log.bz2 | sed -e 's/\.log\.bz2/\.log/g')
nlogs=$(echo $logs | wc -w)
if [ $nlogs -eq 0 ]; then
echo "No errors" >>$of;
else
num=0
echo "<table border=1>" >>$of
echo "<tr><th>Log</th></tr>" >>$of
for i in $logs; do
if [ -f ${fdir2}/${i}.bz2 -o -f ${fdir2}/${i} ]; then
fname1=$(basename $i .bz2)
fname=$(basename $fname1 .log)
echo -n "<tr>" >> $of
echo -n "<td><a href=\"$arch-$dir1/$fname.log\">$fname</a></td>" >>$of
echo -n "<td><a href=\"$arch-$dir2/$fname.log\">$fname</a></td>" >>$of
echo "</tr>" >>$of
num=$(($num + 1))
fi
done
echo "</table><br>" >> $of
echo "$num errors<br>" >> $of
fi
echo "<hr>" >> $of
echo "<a href=\"../\">back to top</a>" >> $of
echo "</body></html>" >>$of
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