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#!/bin/sh
#
# Runs in the background on the server. This script keeps track of
# the relative loads of the client machines, and specifies which machine(s)
# should be handed new jobs, according to the following algorithm:
#
# For each machine listed in ${buildroot}/mlist, check whether its load
# information has been updated in the last 15 seconds (should be updated by
# the reportload script every 5 seconds). If so, then divide the number of
# running jobs on the client by its weighting in mlist, and output the
# machine(s) with the minimum value to ${buildroot}/ulist.
#
# Dividing by the weight has the effect of grouping machines with similar
# job load (e.g. a weight of 5 will rank machines with job loads 0, 1, 2, 3, 4
# as the same; if the machines all had a weight of 1 then it would only
# choose the machine with the least value of the job load, and would probably
# choose a single machine most of the time).
buildroot=/var/portbuild
mlist=${buildroot}/mlist
stamp=${buildroot}/loads/.stamp
unset DISPLAY
while true; do
touch ${stamp}
sleep 15
min=99
set $(cat $mlist)
while [ $# -gt 1 ]; do
m=$1
l=$2
if [ -f ${buildroot}/loads/$m -a \
! -z "$(find ${buildroot}/loads/$m -newer ${stamp})" ]; then
num=$(awk '{print $1}' ${buildroot}/loads/$m)
if [ "x$num" = "x" ]; then
# logger "checkmachines: file ${buildroot}/loads/$m is empty"
num=99
fi
else
num=99
fi
#xxx
#xxx Need to figure out how this is happening and fix this script
#xxx accordingly. This is what causes this script to go away on
#xxx occasion.
#xxx
#xxx arith: syntax error: "7:53AM / 5"
#xxx
num=$(($num / $l))
if [ $num -lt $min ]; then
mach=$m
min=$num
elif [ $num = $min ]; then
mach="$mach $m"
fi
shift 2
done
echo "$mach" > ${buildroot}/ulist
done
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